type 3 addition subtraction product on ratio & proportion Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16 [SSC CGL Tier-I 2012]

The number to be added to each of the numbers 7, 16, 43, 79 to make the numbers in proportion is

a) 5

b) 1

c) 3

d) 2

Answer: (a)

From the given options number = 5, because

${7 + 5}/{16 + 5} = {43 + 5}/{79 + 5}$

$12/21 = 48/84$

[check other options likewise]

Using Rule 32,

Here, a = 7, b=16, c = 43, d= 79

Required number

x= ${bc - ad}/{(a+d) - (b+c)}$

= ${16 × 43 - 7 × 79}/{(7 + 79) - (16 + 43)}$

= ${688 - 553}/{86 - 79}$

= $35/7$ = 5

Question : 17 [SSC DEO 2009]

Which number when added to each of the numbers 6, 7, 15, 17 will make the resulting numbers proportional ?

a) 4

b) 3

c) 5

d) 6

Answer: (b)

Let required number be x.

${6 +x}/{7 + x} = {15 + x}/{17 + x}$

$102 + 17x + 6x + x^2$

= $105 + 7x + 15x + x^2$

23x - 22x = 105 - 102

x = 3

Note : It is convenient to solve it orally using options

${6 + 3}/{7 + 3} = {15 + 3}/{17 + 3}$

= $9/10 = 18/20$

Using Rule 32
Let 'x' be a number which is subtracted from a, b, c and d to make them proportional, then
x = ${ad - bc}/{(a+d) - (b+c)}$
Let 'x' be a number which is added to a, b, c and d to make them proportional, then
x = ${bc - ad}/{(a+d) - (b+c)}$
Here, a, b, c and d should always be in ascending order.

Required Number

= ${bc - ad}/{(a+d) - (b+c)}$

Where a = 6, b = 7, c = 15, d = 17

= ${7 × 15 - 6 × 17}/{(6 + 17) - (7 + 15)}$

= ${105 - 102}/{23 - 22}$ = 3

Question : 18 [SSC CGL Tier-I 2015]

If A and B are in the ratio 4 : 5 and the difference of their squares is 81, what is the value of A ?

a) 36

b) 15

c) 12

d) 45

Answer: (c)

Let A = 4x and B = 5x.

According to the question,

$(5x)^2 - (4x)^2$ = 81

$25x^2 - 16x^2$ = 81

$9x^2 = 81 ⇒ x^2$ = 9

$x = √9$ = 3

A = 4x = 4 × 3 = 12

Question : 19 [SSC CGL Tier-I 2010]

Two numbers are in the ratio 1 : 3. If their sum is 240, then their difference is

a) 100

b) 96

c) 108

d) 120

Answer: (d)

Let the numbers be 3x and x,

Then, 3x + x = 240

4x = 240

$x = 240/4$ = 60

Difference = 3x - x = 2x

= 2 × 60 = 120

Question : 20 [SSC CGL Tier-1 2011]

Three numbers are in the ratio 3 : 4 : 5. The sum of the largest and the smallest equals the sum of the second and 52. The smallest number is

a) 39

b) 52

c) 27

d) 20

Answer: (a)

Let the numbers be 3x, 4x and 5x.

5x + 3x = 4x + 52

4x = 52 ⇒ x =13

The smallest number

= 3x = 3 × 13 = 39

IMPORTANT quantitative aptitude EXERCISES

type 3 addition subtraction product on ratio & proportion Online Quiz

Click to Start..

Recently Added Subject & Categories For All Competitive Exams

100+ Quadratic Equation Questions Answers PDF for Bank

Quadratic Equation multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

IBPS Aptitude Linear Equations MCQ Questions Answers PDF

Linear equations multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »